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2/5x+3=7/10+x
We move all terms to the left:
2/5x+3-(7/10+x)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 10+x)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
x)!=-10
x!=-10/1
x!=-10
x∈R
2/5x-(+x+7/10)+3=0
We get rid of parentheses
2/5x-x+3-7/10=0
We calculate fractions
There is no solution for this equation
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