4(m+2)+3(m-2)=16

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Solution for 4(m+2)+3(m-2)=16 equation: 


Simplifying
4(m + 2) + 3(m + -2) = 16

Reorder the terms:
4(2 + m) + 3(m + -2) = 16
(2 * 4 + m * 4) + 3(m + -2) = 16
(8 + 4m) + 3(m + -2) = 16

Reorder the terms:
8 + 4m + 3(-2 + m) = 16
8 + 4m + (-2 * 3 + m * 3) = 16
8 + 4m + (-6 + 3m) = 16

Reorder the terms:
8 + -6 + 4m + 3m = 16

Combine like terms: 8 + -6 = 2
2 + 4m + 3m = 16

Combine like terms: 4m + 3m = 7m
2 + 7m = 16

Solving
2 + 7m = 16

Solving for variable 'm'.

Move all terms containing m to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + 7m = 16 + -2

Combine like terms: 2 + -2 = 0
0 + 7m = 16 + -2
7m = 16 + -2

Combine like terms: 16 + -2 = 14
7m = 14

Divide each side by '7'.
m = 2

Simplifying
m = 2

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