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x in (-oo:+oo)
q-((5*z)/5) = 5*k-((5*z)/5) // - 5*k-((5*z)/5)
q-(5*k)-((5*z)/5)+(5*z)/5 = 0
q-5*k-z+(5*z)/5 = 0
q-5*k = 0
x należy do R
x in (-oo:+oo)
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