4(m+1)+3=2m-2(m-3)

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Solution for 4(m+1)+3=2m-2(m-3) equation: 



4(m+1)+3=2m-2(m-3)

We move all terms to the left:

4(m+1)+3-(2m-2(m-3))=0

We multiply parentheses

4m-(2m-2(m-3))+4+3=0



We calculate terms in parentheses: -(2m-2(m-3)), so:

2m-2(m-3)

We multiply parentheses

2m-2m+6

We add all the numbers together, and all the variables

6

Back to the equation:

-(6)



We add all the numbers together, and all the variables

4m+1=0

We move all terms containing m to the left, all other terms to the right

4m=-1

m=-1/4

m=-1/4

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