36x2=13+30

Solution for 36x2=13+30 equation:

36x^2=13+30

We move all terms to the left:

36x^2-(13+30)=0

We add all the numbers together, and all the variables

36x^2-43=0

a = 36; b = 0; c = -43;
Δ = b2-4ac
Δ = 02-4·36·(-43)
Δ = 6192
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{6192}=\sqrt{144*43}=\sqrt{144}*\sqrt{43}=12\sqrt{43}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{43}}{2*36}=\frac{0-12\sqrt{43}}{72}
=-\frac{12\sqrt{43}}{72}
=-\frac{\sqrt{43}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{43}}{2*36}=\frac{0+12\sqrt{43}}{72}
=\frac{12\sqrt{43}}{72}
=\frac{\sqrt{43}}{6}
$