4(k-3)=8(k+1)

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Solution for 4(k-3)=8(k+1) equation: 



4(k-3)=8(k+1)

We move all terms to the left:

4(k-3)-(8(k+1))=0

We multiply parentheses

4k-(8(k+1))-12=0



We calculate terms in parentheses: -(8(k+1)), so:

8(k+1)

We multiply parentheses

8k+8

Back to the equation:

-(8k+8)



We get rid of parentheses

4k-8k-8-12=0

We add all the numbers together, and all the variables

-4k-20=0

We move all terms containing k to the left, all other terms to the right

-4k=20

k=20/-4

k=-5

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