20+2x=2(10-3x)+8x

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Solution for 20+2x=2(10-3x)+8x equation: 



20+2x=2(10-3x)+8x

We move all terms to the left:

20+2x-(2(10-3x)+8x)=0

We add all the numbers together, and all the variables

2x-(2(-3x+10)+8x)+20=0



We calculate terms in parentheses: -(2(-3x+10)+8x), so:

2(-3x+10)+8x

We add all the numbers together, and all the variables

8x+2(-3x+10)

We multiply parentheses

8x-6x+20

We add all the numbers together, and all the variables

2x+20

Back to the equation:

-(2x+20)



We get rid of parentheses

2x-2x-20+20=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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