4(k-3)=2=(2k-6)

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Solution for 4(k-3)=2=(2k-6) equation: 



4(k-3)=2=(2k-6)

We move all terms to the left:

4(k-3)-(2)=0

We multiply parentheses

4k-12-2=0

We add all the numbers together, and all the variables

4k-14=0

We move all terms containing k to the left, all other terms to the right

4k=14

k=14/4

k=3+1/2

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