4(3b+23)=12+32b

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Solution for 4(3b+23)=12+32b equation: 



4(3b+23)=12+32b

We move all terms to the left:

4(3b+23)-(12+32b)=0

We add all the numbers together, and all the variables

4(3b+23)-(32b+12)=0

We multiply parentheses

12b-(32b+12)+92=0

We get rid of parentheses

12b-32b-12+92=0

We add all the numbers together, and all the variables

-20b+80=0

We move all terms containing b to the left, all other terms to the right

-20b=-80

b=-80/-20

b=+4

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