4(k-3)=2-(k-6)

Solution for 4(k-3)=2-(k-6) equation:

4(k-3)=2-(k-6)

We move all terms to the left:

4(k-3)-(2-(k-6))=0

We multiply parentheses

4k-(2-(k-6))-12=0


We calculate terms in parentheses: -(2-(k-6)), so:

2-(k-6)

determiningTheFunctionDomain
-(k-6)+2

We get rid of parentheses

-k+6+2

We add all the numbers together, and all the variables

-1k+8

Back to the equation:

-(-1k+8)


We get rid of parentheses

4k+1k-8-12=0

We add all the numbers together, and all the variables

5k-20=0

We move all terms containing k to the left, all other terms to the right

5k=20

k=20/5

k=4