4(k-3)=12-(2k+6)

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Solution for 4(k-3)=12-(2k+6) equation: 



4(k-3)=12-(2k+6)

We move all terms to the left:

4(k-3)-(12-(2k+6))=0

We multiply parentheses

4k-(12-(2k+6))-12=0



We calculate terms in parentheses: -(12-(2k+6)), so:

12-(2k+6)

determiningTheFunctionDomain
-(2k+6)+12

We get rid of parentheses

-2k-6+12

We add all the numbers together, and all the variables

-2k+6

Back to the equation:

-(-2k+6)



We get rid of parentheses

4k+2k-6-12=0

We add all the numbers together, and all the variables

6k-18=0

We move all terms containing k to the left, all other terms to the right

6k=18

k=18/6

k=3

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