7(4-z)/6=z

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Solution for 7(4-z)/6=z equation:



7(4-z)/6=z
We move all terms to the left:
7(4-z)/6-(z)=0
We add all the numbers together, and all the variables
7(-1z+4)/6-z=0
We add all the numbers together, and all the variables
-1z+7(-1z+4)/6=0
We multiply all the terms by the denominator
-1z*6+7(-1z+4)=0
We multiply parentheses
-1z*6-7z+28=0
Wy multiply elements
-6z-7z+28=0
We add all the numbers together, and all the variables
-13z+28=0
We move all terms containing z to the left, all other terms to the right
-13z=-28
z=-28/-13
z=2+2/13

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