4(k-2)=3(2k-6)

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Solution for 4(k-2)=3(2k-6) equation: 



4(k-2)=3(2k-6)

We move all terms to the left:

4(k-2)-(3(2k-6))=0

We multiply parentheses

4k-(3(2k-6))-8=0



We calculate terms in parentheses: -(3(2k-6)), so:

3(2k-6)

We multiply parentheses

6k-18

Back to the equation:

-(6k-18)



We get rid of parentheses

4k-6k+18-8=0

We add all the numbers together, and all the variables

-2k+10=0

We move all terms containing k to the left, all other terms to the right

-2k=-10

k=-10/-2

k=+5

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