4(k-2)=2k-18

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Solution for 4(k-2)=2k-18 equation: 



4(k-2)=2k-18

We move all terms to the left:

4(k-2)-(2k-18)=0

We multiply parentheses

4k-(2k-18)-8=0

We get rid of parentheses

4k-2k+18-8=0

We add all the numbers together, and all the variables

2k+10=0

We move all terms containing k to the left, all other terms to the right

2k=-10

k=-10/2

k=-5

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