-7(1+2b)=-3(4b+3)-6

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Solution for -7(1+2b)=-3(4b+3)-6 equation: 



-7(1+2b)=-3(4b+3)-6

We move all terms to the left:

-7(1+2b)-(-3(4b+3)-6)=0

We add all the numbers together, and all the variables

-7(2b+1)-(-3(4b+3)-6)=0

We multiply parentheses

-14b-(-3(4b+3)-6)-7=0



We calculate terms in parentheses: -(-3(4b+3)-6), so:

-3(4b+3)-6

We multiply parentheses

-12b-9-6

We add all the numbers together, and all the variables

-12b-15

Back to the equation:

-(-12b-15)



We get rid of parentheses

-14b+12b+15-7=0

We add all the numbers together, and all the variables

-2b+8=0

We move all terms containing b to the left, all other terms to the right

-2b=-8

b=-8/-2

b=+4

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