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-7/4x-1/4-3/2x=-43/16
We move all terms to the left:
-7/4x-1/4-3/2x-(-43/16)=0
Domain of the equation: 4x!=0
x!=0/4
x!=0
x∈R
Domain of the equation: 2x!=0We get rid of parentheses
x!=0/2
x!=0
x∈R
-7/4x-3/2x-1/4+43/16=0
We calculate fractions
(-256x^2)/2048x^2+2752x^2/2048x^2+(-3584x)/2048x^2+(-3072x)/2048x^2=0
We multiply all the terms by the denominator
(-256x^2)+2752x^2+(-3584x)+(-3072x)=0
We add all the numbers together, and all the variables
2752x^2+(-256x^2)+(-3584x)+(-3072x)=0
We get rid of parentheses
2752x^2-256x^2-3584x-3072x=0
We add all the numbers together, and all the variables
2496x^2-6656x=0
a = 2496; b = -6656; c = 0;
Δ = b2-4ac
Δ = -66562-4·2496·0
Δ = 44302336
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{44302336}=6656$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6656)-6656}{2*2496}=\frac{0}{4992} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6656)+6656}{2*2496}=\frac{13312}{4992} =2+2/3 $
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