4(k+3)+7=2K-(k+8)

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Solution for 4(k+3)+7=2K-(k+8) equation: 



4(k+3)+7=2-(k+8)

We move all terms to the left:

4(k+3)+7-(2-(k+8))=0

We multiply parentheses

4k-(2-(k+8))+12+7=0



We calculate terms in parentheses: -(2-(k+8)), so:

2-(k+8)

determiningTheFunctionDomain
-(k+8)+2

We get rid of parentheses

-k-8+2

We add all the numbers together, and all the variables

-1k-6

Back to the equation:

-(-1k-6)



We add all the numbers together, and all the variables

4k-(-1k-6)+19=0

We get rid of parentheses

4k+1k+6+19=0

We add all the numbers together, and all the variables

5k+25=0

We move all terms containing k to the left, all other terms to the right

5k=-25

k=-25/5

k=-5

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