4(k+2)-7(4K+3)=59

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Solution for 4(k+2)-7(4K+3)=59 equation: 



4(k+2)-7(4+3)=59

We move all terms to the left:

4(k+2)-7(4+3)-(59)=0

determiningTheFunctionDomain
4(k+2)-59-7(4+3)=0

We add all the numbers together, and all the variables

4(k+2)-59-77=0

We add all the numbers together, and all the variables

4(k+2)-136=0

We multiply parentheses

4k+8-136=0

We add all the numbers together, and all the variables

4k-128=0

We move all terms containing k to the left, all other terms to the right

4k=128

k=128/4

k=32

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