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x(x+10)=375
We move all terms to the left:
x(x+10)-(375)=0
We multiply parentheses
x^2+10x-375=0
a = 1; b = 10; c = -375;
Δ = b2-4ac
Δ = 102-4·1·(-375)
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1600}=40$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-40}{2*1}=\frac{-50}{2} =-25 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+40}{2*1}=\frac{30}{2} =15 $
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