4(j-3)=28

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Solution for 4(j-3)=28 equation: 



4(j-3)=28

We move all terms to the left:

4(j-3)-(28)=0

We multiply parentheses

4j-12-28=0

We add all the numbers together, and all the variables

4j-40=0

We move all terms containing j to the left, all other terms to the right

4j=40

j=40/4

j=10

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