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-(2)/(3)x-(3)/(4)x=(5)/(6)
We move all terms to the left:
-(2)/(3)x-(3)/(4)x-((5)/(6))=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: 4x!=0We add all the numbers together, and all the variables
x!=0/4
x!=0
x∈R
-2/3x-3/4x-(+5/6)=0
We get rid of parentheses
-2/3x-3/4x-5/6=0
We calculate fractions
(-240x^2)/432x^2+(-288x)/432x^2+(-324x)/432x^2=0
We multiply all the terms by the denominator
(-240x^2)+(-288x)+(-324x)=0
We get rid of parentheses
-240x^2-288x-324x=0
We add all the numbers together, and all the variables
-240x^2-612x=0
a = -240; b = -612; c = 0;
Δ = b2-4ac
Δ = -6122-4·(-240)·0
Δ = 374544
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{374544}=612$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-612)-612}{2*-240}=\frac{0}{-480} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-612)+612}{2*-240}=\frac{1224}{-480} =-2+11/20 $
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