4(j-12)=20

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Solution for 4(j-12)=20 equation: 



4(j-12)=20

We move all terms to the left:

4(j-12)-(20)=0

We multiply parentheses

4j-48-20=0

We add all the numbers together, and all the variables

4j-68=0

We move all terms containing j to the left, all other terms to the right

4j=68

j=68/4

j=17

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