40=-1/3(9x+3)+2

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Solution for 40=-1/3(9x+3)+2 equation: 



40=-1/3(9x+3)+2

We move all terms to the left:

40-(-1/3(9x+3)+2)=0



Domain of the equation: 3(9x+3)+2)!=0

x∈R



We multiply all the terms by the denominator


-(-1+40*3(9x+3)+2)=0



We calculate terms in parentheses: -(-1+40*3(9x+3)+2), so:

-1+40*3(9x+3)+2

determiningTheFunctionDomain
40*3(9x+3)-1+2

We add all the numbers together, and all the variables

40*3(9x+3)+1

Wy multiply elements

120x(9+1

Back to the equation:

-(120x(9+1)



We add all the numbers together, and all the variables

-(120x10=0

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