4(h-7)=7(h+1)

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Solution for 4(h-7)=7(h+1) equation: 



4(h-7)=7(h+1)

We move all terms to the left:

4(h-7)-(7(h+1))=0

We multiply parentheses

4h-(7(h+1))-28=0



We calculate terms in parentheses: -(7(h+1)), so:

7(h+1)

We multiply parentheses

7h+7

Back to the equation:

-(7h+7)



We get rid of parentheses

4h-7h-7-28=0

We add all the numbers together, and all the variables

-3h-35=0

We move all terms containing h to the left, all other terms to the right

-3h=35

h=35/-3

h=-11+2/3

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