2(4x+3)=3(-2x-4)

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Solution for 2(4x+3)=3(-2x-4) equation: 



2(4x+3)=3(-2x-4)

We move all terms to the left:

2(4x+3)-(3(-2x-4))=0

We multiply parentheses

8x-(3(-2x-4))+6=0



We calculate terms in parentheses: -(3(-2x-4)), so:

3(-2x-4)

We multiply parentheses

-6x-12

Back to the equation:

-(-6x-12)



We get rid of parentheses

8x+6x+12+6=0

We add all the numbers together, and all the variables

14x+18=0

We move all terms containing x to the left, all other terms to the right

14x=-18

x=-18/14

x=-1+2/7

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