4(h+21)=3(h-2)

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Solution for 4(h+21)=3(h-2) equation: 



4(h+21)=3(h-2)

We move all terms to the left:

4(h+21)-(3(h-2))=0

We multiply parentheses

4h-(3(h-2))+84=0



We calculate terms in parentheses: -(3(h-2)), so:

3(h-2)

We multiply parentheses

3h-6

Back to the equation:

-(3h-6)



We get rid of parentheses

4h-3h+6+84=0

We add all the numbers together, and all the variables

h+90=0

We move all terms containing h to the left, all other terms to the right

h=-90

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