(8i)(-8i)=0

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Solution for (8i)(-8i)=0 equation: 



(8i)(-8i)=0

We multiply parentheses

-64i^2=0

a = -64; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-64)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$i=\frac{-b}{2a}=\frac{0}{-128}=0$

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