4(g+2)=3(g-1)

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Solution for 4(g+2)=3(g-1) equation: 



4(g+2)=3(g-1)

We move all terms to the left:

4(g+2)-(3(g-1))=0

We multiply parentheses

4g-(3(g-1))+8=0



We calculate terms in parentheses: -(3(g-1)), so:

3(g-1)

We multiply parentheses

3g-3

Back to the equation:

-(3g-3)



We get rid of parentheses

4g-3g+3+8=0

We add all the numbers together, and all the variables

g+11=0

We move all terms containing g to the left, all other terms to the right

g=-11

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