4(f+3)=2(f-7)

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Solution for 4(f+3)=2(f-7) equation: 



4(f+3)=2(f-7)

We move all terms to the left:

4(f+3)-(2(f-7))=0

We multiply parentheses

4f-(2(f-7))+12=0



We calculate terms in parentheses: -(2(f-7)), so:

2(f-7)

We multiply parentheses

2f-14

Back to the equation:

-(2f-14)



We get rid of parentheses

4f-2f+14+12=0

We add all the numbers together, and all the variables

2f+26=0

We move all terms containing f to the left, all other terms to the right

2f=-26

f=-26/2

f=-13

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