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6(5b+7)=2+5(5b-7)
We move all terms to the left:
6(5b+7)-(2+5(5b-7))=0
We multiply parentheses
30b-(2+5(5b-7))+42=0
We calculate terms in parentheses: -(2+5(5b-7)), so:We get rid of parentheses
2+5(5b-7)
determiningTheFunctionDomain 5(5b-7)+2
We multiply parentheses
25b-35+2
We add all the numbers together, and all the variables
25b-33
Back to the equation:
-(25b-33)
30b-25b+33+42=0
We add all the numbers together, and all the variables
5b+75=0
We move all terms containing b to the left, all other terms to the right
5b=-75
b=-75/5
b=-15
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