4(d-8)=5(d+3)

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Solution for 4(d-8)=5(d+3) equation: 



4(d-8)=5(d+3)

We move all terms to the left:

4(d-8)-(5(d+3))=0

We multiply parentheses

4d-(5(d+3))-32=0



We calculate terms in parentheses: -(5(d+3)), so:

5(d+3)

We multiply parentheses

5d+15

Back to the equation:

-(5d+15)



We get rid of parentheses

4d-5d-15-32=0

We add all the numbers together, and all the variables

-1d-47=0

We move all terms containing d to the left, all other terms to the right

-d=47

d=47/-1

d=-47

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