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(2x+5)=(65-2x)
We move all terms to the left:
(2x+5)-((65-2x))=0
We add all the numbers together, and all the variables
(2x+5)-((-2x+65))=0
We get rid of parentheses
2x-((-2x+65))+5=0
We calculate terms in parentheses: -((-2x+65)), so:We get rid of parentheses
(-2x+65)
We get rid of parentheses
-2x+65
Back to the equation:
-(-2x+65)
2x+2x-65+5=0
We add all the numbers together, and all the variables
4x-60=0
We move all terms containing x to the left, all other terms to the right
4x=60
x=60/4
x=15
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