4(d-4)2=3(d+1)

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Solution for 4(d-4)2=3(d+1) equation: 



4(d-4)2=3(d+1)

We move all terms to the left:

4(d-4)2-(3(d+1))=0

We multiply parentheses

8d-(3(d+1))-32=0



We calculate terms in parentheses: -(3(d+1)), so:

3(d+1)

We multiply parentheses

3d+3

Back to the equation:

-(3d+3)



We get rid of parentheses

8d-3d-3-32=0

We add all the numbers together, and all the variables

5d-35=0

We move all terms containing d to the left, all other terms to the right

5d=35

d=35/5

d=7

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