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0.06x(x-5)+0.8(x-6)=0.2x-1.8
We move all terms to the left:
0.06x(x-5)+0.8(x-6)-(0.2x-1.8)=0
We multiply parentheses
0x^2+0x+0.8x-(0.2x-1.8)-4.8=0
We get rid of parentheses
0x^2+0x+0.8x-0.2x+1.8-4.8=0
We add all the numbers together, and all the variables
x^2+1.6x-3=0
a = 1; b = 1.6; c = -3;
Δ = b2-4ac
Δ = 1.62-4·1·(-3)
Δ = 14.56
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.6)-\sqrt{14.56}}{2*1}=\frac{-1.6-\sqrt{14.56}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.6)+\sqrt{14.56}}{2*1}=\frac{-1.6+\sqrt{14.56}}{2} $
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