4(d+2)=12(3-2d)

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Solution for 4(d+2)=12(3-2d) equation: 



4(d+2)=12(3-2d)

We move all terms to the left:

4(d+2)-(12(3-2d))=0

We add all the numbers together, and all the variables

4(d+2)-(12(-2d+3))=0

We multiply parentheses

4d-(12(-2d+3))+8=0



We calculate terms in parentheses: -(12(-2d+3)), so:

12(-2d+3)

We multiply parentheses

-24d+36

Back to the equation:

-(-24d+36)



We get rid of parentheses

4d+24d-36+8=0

We add all the numbers together, and all the variables

28d-28=0

We move all terms containing d to the left, all other terms to the right

28d=28

d=28/28

d=1

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