3/4(2x+6)=1/3(3x-5)

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Solution for 3/4(2x+6)=1/3(3x-5) equation: 



3/4(2x+6)=1/3(3x-5)

We move all terms to the left:

3/4(2x+6)-(1/3(3x-5))=0



Domain of the equation: 4(2x+6)!=0

x∈R





Domain of the equation: 3(3x-5))!=0

x∈R



We calculate fractions


(9x3/(4(2x+6)*3(3x-5)))+(-4x2/(4(2x+6)*3(3x-5)))=0



We calculate terms in parentheses: +(9x3/(4(2x+6)*3(3x-5))), so:

9x3/(4(2x+6)*3(3x-5))

We multiply all the terms by the denominator


9x3

We add all the numbers together, and all the variables

9x^3

We do not support expression: x^3

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