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(5x-3=)+(6x-8=)
We move all terms to the left:
(5x-3-()+(6x-8)=0
We calculate terms in parentheses: +(5x-3-()+(6x-8), so:x=0/11
5x-3-()+(6x-8
determiningTheFunctionDomain 5x+(6x-8-3-()
We calculate terms in parentheses: +(6x-8-3-(), so:We add all the numbers together, and all the variables
6x-8-3-(
We add all the numbers together, and all the variables
6x
Back to the equation:
+(6x)
11x
Back to the equation:
+(11x)
x=0
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