(4/7)+(7m/5)=(76/35)

Solution for (4/7)+(7m/5)=(76/35) equation:

(4/7)+(7m/5)=(76/35)

We move all terms to the left:

(4/7)+(7m/5)-((76/35))=0

We add all the numbers together, and all the variables

(+7m/5)+(+4/7)-((+76/35))=0

We get rid of parentheses

7m/5+4/7-((+76/35))=0

We calculate fractions


5145m^2/()+()/()+()/()=0

We add all the numbers together, and all the variables

5145m^2/()+2=0

We multiply all the terms by the denominator


5145m^2+2*()=0

We add all the numbers together, and all the variables

5145m^2=0

a = 5145; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·5145·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$m=\frac{-b}{2a}=\frac{0}{10290}=0$