4(c-7)=2(2c-14)

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Solution for 4(c-7)=2(2c-14) equation: 



4(c-7)=2(2c-14)

We move all terms to the left:

4(c-7)-(2(2c-14))=0

We multiply parentheses

4c-(2(2c-14))-28=0



We calculate terms in parentheses: -(2(2c-14)), so:

2(2c-14)

We multiply parentheses

4c-28

Back to the equation:

-(4c-28)



We get rid of parentheses

4c-4c+28-28=0

We add all the numbers together, and all the variables

=0

c=0/1

c=0

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