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3x-5=-8(6/5x)
We move all terms to the left:
3x-5-(-8(6/5x))=0
Domain of the equation: 5x))!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
3x-(-8(+6/5x))-5=0
We multiply all the terms by the denominator
3x*5x))-(-8(-5*5x))+6=0
Wy multiply elements
15x^2-25x=0
a = 15; b = -25; c = 0;
Δ = b2-4ac
Δ = -252-4·15·0
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{625}=25$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-25}{2*15}=\frac{0}{30} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+25}{2*15}=\frac{50}{30} =1+2/3 $
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