4=(2+3z)=

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Solution for 4=(2+3z)= equation: 



4=(2+3z)=

We move all terms to the left:

4-((2+3z))=0

We add all the numbers together, and all the variables

-((3z+2))+4=0



We calculate terms in parentheses: -((3z+2)), so:

(3z+2)

We get rid of parentheses

3z+2

Back to the equation:

-(3z+2)



We get rid of parentheses

-3z-2+4=0

We add all the numbers together, and all the variables

-3z+2=0

We move all terms containing z to the left, all other terms to the right

-3z=-2

z=-2/-3

z=2/3

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