4(c-2)/2=2(2c+5)/5

Solution for 4(c-2)/2=2(2c+5)/5 equation:

4(c-2)/2=2(2c+5)/5

We move all terms to the left:

4(c-2)/2-(2(2c+5)/5)=0

We calculate fractions


4c/()+(-(2(2c+5)*2)/()=0


We calculate terms in parentheses: +(-(2(2c+5)*2)/(), so:

-(2(2c+5)*2)/(

We multiply all the terms by the denominator


-(2(2c+5)*2)


We calculate terms in parentheses: -(2(2c+5)*2), so:

2(2c+5)*2

We multiply parentheses

8c+20

Back to the equation:

-(8c+20)


We get rid of parentheses

-8c-20

Back to the equation:

+(-8c-20)


We get rid of parentheses

4c/()-8c-20=0

We multiply all the terms by the denominator


4c-8c*()-20*()=0

We add all the numbers together, and all the variables

4c-8c*()=0