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10(2x+(3x-8)+1/2)=5x
We move all terms to the left:
10(2x+(3x-8)+1/2)-(5x)=0
We add all the numbers together, and all the variables
-5x+10(2x+(3x-8)+1/2)=0
We multiply all the terms by the denominator
-5x*2)+10(2x+(3x-8)+1=0
Wy multiply elements
-10x^2+(3x-8)+1=0
We get rid of parentheses
-10x^2+3x-8+1=0
We add all the numbers together, and all the variables
-10x^2+3x-7=0
a = -10; b = 3; c = -7;
Δ = b2-4ac
Δ = 32-4·(-10)·(-7)
Δ = -271
Delta is less than zero, so there is no solution for the equation
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