4(c+3)+3=7c

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Solution for 4(c+3)+3=7c equation: 



4(c+3)+3=7c

We move all terms to the left:

4(c+3)+3-(7c)=0

We add all the numbers together, and all the variables

-7c+4(c+3)+3=0

We multiply parentheses

-7c+4c+12+3=0

We add all the numbers together, and all the variables

-3c+15=0

We move all terms containing c to the left, all other terms to the right

-3c=-15

c=-15/-3

c=+5

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