4(c+2)=3(c-2)+1

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Solution for 4(c+2)=3(c-2)+1 equation:


Simplifying
4(c + 2) = 3(c + -2) + 1

Reorder the terms:
4(2 + c) = 3(c + -2) + 1
(2 * 4 + c * 4) = 3(c + -2) + 1
(8 + 4c) = 3(c + -2) + 1

Reorder the terms:
8 + 4c = 3(-2 + c) + 1
8 + 4c = (-2 * 3 + c * 3) + 1
8 + 4c = (-6 + 3c) + 1

Reorder the terms:
8 + 4c = -6 + 1 + 3c

Combine like terms: -6 + 1 = -5
8 + 4c = -5 + 3c

Solving
8 + 4c = -5 + 3c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-3c' to each side of the equation.
8 + 4c + -3c = -5 + 3c + -3c

Combine like terms: 4c + -3c = 1c
8 + 1c = -5 + 3c + -3c

Combine like terms: 3c + -3c = 0
8 + 1c = -5 + 0
8 + 1c = -5

Add '-8' to each side of the equation.
8 + -8 + 1c = -5 + -8

Combine like terms: 8 + -8 = 0
0 + 1c = -5 + -8
1c = -5 + -8

Combine like terms: -5 + -8 = -13
1c = -13

Divide each side by '1'.
c = -13

Simplifying
c = -13

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