8(b+1)-3b=5(b+1)+3

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Solution for 8(b+1)-3b=5(b+1)+3 equation:


Simplifying
8(b + 1) + -3b = 5(b + 1) + 3

Reorder the terms:
8(1 + b) + -3b = 5(b + 1) + 3
(1 * 8 + b * 8) + -3b = 5(b + 1) + 3
(8 + 8b) + -3b = 5(b + 1) + 3

Combine like terms: 8b + -3b = 5b
8 + 5b = 5(b + 1) + 3

Reorder the terms:
8 + 5b = 5(1 + b) + 3
8 + 5b = (1 * 5 + b * 5) + 3
8 + 5b = (5 + 5b) + 3

Reorder the terms:
8 + 5b = 5 + 3 + 5b

Combine like terms: 5 + 3 = 8
8 + 5b = 8 + 5b

Add '-8' to each side of the equation.
8 + -8 + 5b = 8 + -8 + 5b

Combine like terms: 8 + -8 = 0
0 + 5b = 8 + -8 + 5b
5b = 8 + -8 + 5b

Combine like terms: 8 + -8 = 0
5b = 0 + 5b
5b = 5b

Add '-5b' to each side of the equation.
5b + -5b = 5b + -5b

Combine like terms: 5b + -5b = 0
0 = 5b + -5b

Combine like terms: 5b + -5b = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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