4(c+13)=100

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Solution for 4(c+13)=100 equation: 



4(c+13)=100

We move all terms to the left:

4(c+13)-(100)=0

We multiply parentheses

4c+52-100=0

We add all the numbers together, and all the variables

4c-48=0

We move all terms containing c to the left, all other terms to the right

4c=48

c=48/4

c=12

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