4(b-3)=-9(b+10)

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Solution for 4(b-3)=-9(b+10) equation: 



4(b-3)=-9(b+10)

We move all terms to the left:

4(b-3)-(-9(b+10))=0

We multiply parentheses

4b-(-9(b+10))-12=0



We calculate terms in parentheses: -(-9(b+10)), so:

-9(b+10)

We multiply parentheses

-9b-90

Back to the equation:

-(-9b-90)



We get rid of parentheses

4b+9b+90-12=0

We add all the numbers together, and all the variables

13b+78=0

We move all terms containing b to the left, all other terms to the right

13b=-78

b=-78/13

b=-6

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