4(b-2)=2(b-4)+2b

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Solution for 4(b-2)=2(b-4)+2b equation:



4(b-2)=2(b-4)+2b
We move all terms to the left:
4(b-2)-(2(b-4)+2b)=0
We multiply parentheses
4b-(2(b-4)+2b)-8=0
We calculate terms in parentheses: -(2(b-4)+2b), so:
2(b-4)+2b
We add all the numbers together, and all the variables
2b+2(b-4)
We multiply parentheses
2b+2b-8
We add all the numbers together, and all the variables
4b-8
Back to the equation:
-(4b-8)
We get rid of parentheses
4b-4b+8-8=0
We add all the numbers together, and all the variables
=0
b=0/1
b=0

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