2z+3/3z+1=2z-1/3z-2

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Solution for 2z+3/3z+1=2z-1/3z-2 equation: 



2z+3/3z+1=2z-1/3z-2

We move all terms to the left:

2z+3/3z+1-(2z-1/3z-2)=0



Domain of the equation: 3z!=0

z!=0/3

z!=0

z∈R





Domain of the equation: 3z-2)!=0

z∈R



We get rid of parentheses

2z+3/3z-2z+1/3z+2+1=0

We multiply all the terms by the denominator


2z*3z-2z*3z+2*3z+1*3z+3+1=0

We add all the numbers together, and all the variables

2z*3z-2z*3z+2*3z+1*3z+4=0

Wy multiply elements

6z^2-6z^2+6z+3z+4=0

We add all the numbers together, and all the variables

9z+4=0

We move all terms containing z to the left, all other terms to the right

9z=-4

z=-4/9

z=-4/9

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